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== References == | == References == | ||
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* [https://www.youtube.com/watch?v=LNidsMesxSE Animation Bootcamp: An Indie Approach to Procedural Animation] - a [http://www.gdconf.com GDC] talk about character animation in a computation effective way. | * [https://www.youtube.com/watch?v=LNidsMesxSE Animation Bootcamp: An Indie Approach to Procedural Animation] - a [http://www.gdconf.com GDC] talk about character animation in a computation effective way. | ||
+ | * [http://wiki.roblox.com/index.php?title=Inverse_kinematics#FABRIK Inverse kinematics] on roblox via [http://lephas.me/ Sébastien Courvoisier | ||
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[[category:javascript]] | [[category:javascript]] |
Notes about computation of inverse kinematics[1], first implementation done in threejs[2].
At this moment, the research is focusing on solving a 2 bones system, the leg in this case, but it would be applicable on the arms or any other part of a skeleton having at least 2 parents.
The main issue seems to be the computation of the knee position. All distances are easily computed:
Rendering the position of the knee is crucial to compute the rotation of the upper leg. Once correct, the rotation of the leg will be simple to render, as it is the rotation from the current direction to the [knee - target] direction.
A little warning: the graphic here above is in 2d. In a 3d world, the position of the knee is a circle on a sphere: any point being at the right distance of the target point and the upperleg origin will be a valid candidate! The circle of possibilities is the intersection of 2 spheres having their radii equals to bones length.
The radius of the cyan circle can be solved by using this equation[3]:
a = 1/(2d)sqrt(4d^2R^2-(d^2-r^2+R^2)^2)
A little screenshot for better readability:
The tricky point is to forget about the spheres' position and only consider the distance of their centers as the d parameter. The normal of the intersection plane can be computed independently.
Implementation of the equation in an openprocessing sketch.
We need to pick a point on this circle by using an arbitrary direction:
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